++ 50 ++ (ab bc ac)^2 =3abc(a b c) 114818

25 A 2 B 2 3 B 2 C 2 3 C 2 A 2 3 A B 3 B C 3 C A 3

25 A 2 B 2 3 B 2 C 2 3 C 2 A 2 3 A B 3 B C 3 C A 3

Y=C'(A'AB')AC and Y=C'(A'A)(A'B)AC You ate the ' from B Even after that I can't seem to get the expected answer though, but maybe it helps, unless it was a typo EDIT Actually, I think I got it A'B'C' A'BC' AB'C' AB'C ABC Factor out AC on the bold ones and A'C' on the italic ones A'C'(B'B) AB'C' AC(B' B) Y = A'C Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries Students (upto class 102) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (MainsAdvance) and NEET can ask questions from any subject and get quick answers by

(ab bc ac)^2 =3abc(a b c)

(ab bc ac)^2 =3abc(a b c)-And for (A;B;C) = (k;k 1;k 2)\mathtt{\Longrightarrow \ ( x)^{3} ( 3)^{3} ( 4y)^{3} 3( x)( 3)( 4y)}\\\ \\ \mathtt{\Longrightarrow \ x^{3} 964y^{3} 36xy} Hence, the above expression is the solution

Using The Properties Of Determinants Prove The Following A B C A B B C C A B C C A A B A 3 B 3 C 3 3abc Sarthaks Econnect Largest Online Education Community

Using The Properties Of Determinants Prove The Following A B C A B B C C A B C C A A B A 3 B 3 C 3 3abc Sarthaks Econnect Largest Online Education Community

 What must be subtracted from 4x^42x^36x^22x6 so that the result is exactly divisible by 2x^2x1? (abc)^3 = a^3 b^3 c^3 3a^2b 3a^2c 3ab^2 3ac^2 3b^2c 3bc^2 6abc (abc)(abacbc) = a^2b a^2c ab^2 ac^2 3abc so, that means that (abc)^3 3(abc)(abacbc) = a^3 b^3 c^3 3abc Now just plug in your numbers1 Inform you about time table of exam 2 Inform you about new question papers 3 New video tutorials information

Chứng minh a3b3c33abc=(abc)(a2b2c2abbcca) HOC24 Lớp học (abc\right)\left(a^2b^2c^2abacbc\right)\) Đúng 0 Bình luận (0) Đinh Tuấn Việt 7 tháng 6 16 lúc 1135 Đặt A = a 3 b 3 c 3 3abc (đpcm) Đúng 0\mathtt{( abc)\left( a^{2} b^{2} c^{2} abbcca\right)}\\ \\ \mathtt{=a^{3} b^{3} c^{3} 3abc} Where; Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries Students (upto class 102) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (MainsAdvance) and NEET can ask questions from any subject and get quick answers by

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`a^2b ab^2 b^2c bc^2 ac^2 a^2c 3abc` We need to group these terms in a way so that we could find some common factors Now there are 7 terms in the expression, which is not a veryRút gọn biểu thức A= (a^3b^3c^33abc)/ (a^2b^2c^2abbcca) Rút gọn biểu thức A= (a^3b^3c^33abc)/ (a^2b^2c^2abbcca) Theo dõi Vi phạm ADSENSE

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